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Warmtekapasiteit: Verskil tussen weergawes

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Lyn 157:
 
<math>Q = \int_{T_1}^{T_2} C_p \, dT</math>
 
<math>Q = \int_{800}^{400} 9.01 + 0.00202T + 1.34 \times 10^{-7}T^2 - \frac{117300}{T^2} \, dT</math>
 
<math>= \left | 9.01T + \frac{0.00202}{2}T^2 + \frac{1.34 \times 10^{-7}}{3} T^3 - \frac{117300}{-1} T^{-1} \right |_{800}^{400}</math>
 
 
<math>= \left ([ 9.01T01(400) + \frac{0.00202}{2}T(400)^2 + \frac{1.34 \times 10^{-7}}{3} T(400)^3 - \frac{117300}{-1} T(400)^{-1} \right ] - \left [ 9.01(800) |_+ \frac{0.00202}{2}(800)^2 + \frac{1.34 \times 10^{-7}}{3}(800)^3 - \frac{400117300}{-1}(800)^{-1} \right ]</math>
 
 
 
<math> \left | A \right |_800^200 </math>
 
 
<math> 117300/(-1).T-1 \right | </math>
 
<math>= 4050 kal/mol</math>
 
(9.01.T + 0.00202/2.T2 + 1.34e-7/3.T3 – 117300/(-1).T-1)|800400
= ~ 4050 kal/mol
 
Energieverlies = 4050* × 4.1868* × 0.04 = ~ 680 kJ/h
= ~ 680 kJ/h
 
== Sien ook ==
Ontsluit van "https://af.wikipedia.org/wiki/Warmtekapasiteit"