Warmtekapasiteit: Verskil tussen weergawes

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Lyn 182:
'''Antwoord:'''
 
Stoomvloei: 55 t/h × 55x1000(1000 kg/t) / (18 kmg/kmol)= 3056 kmol/h
 
Suurstofvloei: 10 km3n/h  10*1000/22.413 = 446.2 kmol/h
Suurstofvloei: 10 km<sup>3</sup><sub>n</sub>/h × (1000 m<sup>3</sup><sub>n</sub>/km<sup>3</sup><sub>n</sub>) / (22.413 m<sup>3</sup><sub>n</sub>/kmol) = 446.2 kmol/h
Agent:
 
 
Mengsel:
- Vloei = 3502 kmol/h
- Xstoom = 3056/3502 = 87.3% (molfraksie)