Warmtekapasiteit: Verskil tussen weergawes

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Lyn 192:
Totale vloei van mengsel: m<sub>mengsel</sub> = 3056 + 446 = 3502 kmol/h
 
Molfraksie van stoom: X<sub>stoomstm</sub> = 3056/3502 = 87.3%
 
Molfraksie van suurstof: X<sub>suurstofO2</sub> = 446/3502 = 12.7%
 
 
Warmtekapasiteite volgens Perry's Chemical Engineering Handbook, Volume 6, 3-132:
 
:<math>C_{p,O2stm} = 8.2722 + 0.000258T00015T - \frac{1877001.34 \times 10^{-6}}{T^2} \qquad [kal/mol \ (T \ in \ Kelvin)]</math>
 
:<math>C_{p,stmO2} = 8.2227 + 0.00015T000258T - \frac{1.34 \times 10^{-6}187700}{T^2} \qquad [kal/mol \ (T \ in \ Kelvin)]</math>
 
:<math>C_{p,mengsel} = X_{O2stm}.C_{p,O2stm} + X_{stmO2}.C_{p,stmO2} = 8.226 + 0.0001637T + 1.170 \times 10^{-6}T^2 - \frac{23838}{T^2}\qquad [kal/mol \ (T \ in \ Kelvin)]</math>
 
 
Volgens 'n energiebalans:
 
:<math>H_{O2stm} + H_{stmO2} = H_{mengsel}</math>
 
 
Werk nou die entalpie van elke stroom uit deur gebruik te maak van die warmtekapasiteit (gebruik 0 °C as verwysing):
 
'''Entalpie van suurstofstoom:'''
 
<math>QH_{stm} = m \int_{T_1273}^{T_2673} C_pC_{p,stm} \, dT</math>
 
<math>H_{O2} = m_{O2stm} \int_{273}^{373673} C_8.22 + 0.00015T + 1.34 \times 10^{p,O2-6}T^2 \, dT</math>
 
<math>= 3056 \int_{273}^{373}times \left | 8.2722T + \frac{0.000258T00015}{2}T^2 -+ \frac{1877001.34 \times 10^{-6}}{3}T^2}3 \,right dT|_{273}^{673}</math>
 
<math>= 446.23056 \times \left |( 8.27T22(673-273) + \frac{0.00025800015}{2}T(673^2 -273^2) + \frac{187700}{-1}T.34 \times 10^{-16}}{3}(673^3-273^3) \right |_{273}^{373})</math>
 
<math>= 446.2 \times \left ( 8.27(373-273) + \frac{0.000258}{2}(373^2-273^2) + 187700 ( \frac{1}{373}-\frac{1}{273} ) \right )</math>
 
= X kkal
 
 
'''Entalpie van stoomsuurstof:'''
 
<math>H_{stm}Q = m \int_{273T_1}^{673T_2} C_{p,stm}C_p \, dT</math>
 
<math>H_{O2} = m_{stmO2} \int_{273}^{673373} 8.22 + 0.00015T + 1.34 \times 10^C_{-6p,O2}T^2 \, dT</math>
 
<math>= 3056 \times \left |int_{273}^{373} 8.22T27 + \frac{0.00015}{2}T^2000258T +- \frac{1.34 \times 10^{-6}187700}{3}T^32} \right, |_{273}^{673}dT</math>
 
<math>= 3056446.2 \times \left (| 8.22(673-273)27T + \frac{0.00015000258}{2}(673T^2 -273^2) + \frac{187700}{-1.34 \times 10}T^{-61}}{3}(673^3-273^3) \right )|_{273}^{373}</math>
 
<math>= 446.2 \times \left ( 8.27(373-273) + \frac{0.000258}{2}(373^2-273^2) + 187700 ( \frac{1}{373}-\frac{1}{273} ) \right )</math>
 
= Y kkal
Lyn 251:
<math>Z = 3502 \times \left ( 8.226(T-273) + \frac{0.0001637}{2}(T^2-273^2) + \frac{1.170 \times 10^{-6}}{3}(T^3-273^3) - \frac{23838}{-1}(\frac{1}{T}-\frac{1}{273}) \right )</math>
 
Stel nou <math>H_{O2stm} + H_{stmO2} = H_{mengsel}</math> en los vir T op.
 
== Sien ook ==