Antoine-vergelyking: Verskil tussen weergawes

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Lyn 3:
== Die vergelyking ==
 
:<math>\log_{10} p = A-\frac{B}{C+T} \quad \Rightarrow \quad p = 10^{\left ( A-\frac{B}{C+T} \right )}</math>
 
of
 
:<math>\ln p = A-\frac{B}{C+T} \quad \Rightarrow \quad p = e^{\left ( A-\frac{B}{C+T} \right )}</math>
 
Waar: