Antoine-vergelyking: Verskil tussen weergawes
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Robot voeg by: Kategorie:Wiskundige vergelykings |
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Lyn 3:
== Die vergelyking ==
: <math>\log_{10} p = A-\frac{B}{C+T} \quad \Rightarrow \quad p = 10^{\left ( A-\frac{B}{C+T} \right )} \quad \Rightarrow \quad T = \frac{B}{A+\log_{10} p}-C</math>
of
: <math>\ln p = A-\frac{B}{C+T} \quad \Rightarrow \quad p = e^{\left ( A-\frac{B}{C+T} \right )} \quad \Rightarrow \quad T = \frac{B}{A+\ln p}-C</math>
Waar:
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