Vloeimeetskyf: Verskil tussen weergawes

Content deleted Content added
Lyn 177:
<math>(1)\qquad Q = C\;A_2\;\sqrt{2\;(P_1-P_2)/\rho}</math>
 
 
=== Bylaag B: Formule in terme van snelheid en oop area ===
=== Bylaag B: Skakel formule om na meer algemene eenhede ===
 
==== Algemene formule ====
 
Die algemene formule vir die vloei deur 'n meetskyf word soos volg gegee:
 
{| class="wikitable"
|-align=center
|
<math>Q_{(m3/s)} = C A_o \sqrt{2 \Delta P_{(Pa)} \over \rho}</math>
|}
 
Die algemene formule kan soos volg omgeskakel word na meer algemene eenhede soos:
 
* <math>V</math> in m<sup>3</sup>/h in plaas van m<sup>3</sup>/s
* <math>\Delta P</math> in kPa in plaas van Pa
* Gaatjiediameter <math>d_o</math> in mm in plaas van <math>A_o</math> in m<sup>2</sup>
* <math>h_w</math> as mm water in plaas van druk
* <math>SG</math> in plaas van <math>\rho</math>
 
<math>\rho</math> bly steeds in kg/m<sup>3</sup>:
 
==== Volumevloeitempo (V), gaatjiediameter (d<sub>o</sub>), drukval (&Delta;P) en digtheid (&rho;) ====
 
<math>V</math> in m<sup>3</sup>/h, <math>\Delta P</math> in kPa, gaatjiediameter <math>d_o</math> in mm en <math>\rho</math> in kg/m<sup>3</sup>:
 
 
:<math>\frac{V}{3600} = C \left[\frac{\pi}{4}\left(\frac{d_o}{1000}\right)^2 \right] \sqrt{2 \Delta P \times 1000 \over \rho}</math>
 
 
:<math>V = 0.0028274 C d_o^2 \sqrt{2000 \Delta P \over \rho}</math>
 
{| class="wikitable"
|-align=center
|
<math>V = C d_o^2 \sqrt{\Delta P \over 62.544\rho}</math> {{spaces|10}} of {{spaces|10}} <math>\Delta P = \frac{62.243 \rho}{1} \left ( {V \over C d_o^2} \right )^2</math>
|}
 
 
==== Massavloeitempo (W), gaatjiediameter (d<sub>o</sub>), drukval (&Delta;P) en digtheid (&rho;) ====
 
Indien <math>W = \rho V</math>, dan:
 
:<math>\frac{W}{\rho} = C d_o^2 \sqrt{\Delta P \over 62.544\rho}</math>
 
{| class="wikitable"
|-align=center
|
<math>W = C d_o^2 \sqrt{\rho \cdot \Delta P \over 62.544}</math> {{spaces|10}} of {{spaces|10}} <math>\Delta P = \frac{62.243}{\rho} \left ( {W \over C d_o^2} \right )^2</math>
|}
 
==== Volumevloeitempo (V), gaatjiediameter (d<sub>o</sub>), drukval (h<sub>w</sub>) en vloeistof SG) ====
 
As:
 
:<math>Q \qquad \Rightarrow \qquad \frac{V}{3600}</math>
 
:<math>A_o = \frac{\pi}{4}\left(\frac{d_o}{1000}\right)^2</math>
 
:<math>\Delta P_{(Pa)} = \rho g \frac{h_w}{1000} = \frac{1000 \times 9.81 \times h_w}{1000} = 9.81 \times h_w</math>
 
:<math>SG = \frac{\rho}{\rho_{van\ water\ by\ 4^\circ C}} \qquad \Rightarrow \qquad \rho = 1000 \times SG</math>
 
Dan is:
 
:<math>\frac{V}{3600} = C \left[\frac{\pi}{4}\left(\frac{d_o}{1000}\right)^2 \right] \sqrt{2 \times 9.81 \times h_w \over 1000 \times SG}</math>
 
 
:::<math>\frac{3600 \times \pi}{4 \times 1000000} \times \sqrt{\frac{2 \times 9.81}{1000}} = 0.00039604</math>
 
{| class="wikitable"
|-align=center
|
<math>V = 0.00039604 C d_o^2 \sqrt{h_w \over SG}</math>
|}
 
=== Bylaag C: Formule in terme van snelheid en oop area ===
 
Die meetskyfvergelyking kan ook herskryf word in terme van vloeisnelheid <math>v</math> en % opening <math>\alpha</math>:
Line 209 ⟶ 286:
* <math>C</math> = Meetskyfvloeikoëffisiënt ~ 0.692
 
=== Bylaag CD: Afleiding van formules vir vloeikompensasie ===
 
Gebruik die volgende meetskyfvergelyking:
Line 277 ⟶ 354:
 
<math>\left (\frac{\dot n}{\dot n_0}\right )^2 = \left (\frac{V_n}{V_{n,0}}\right )^2 = \frac{P}{P_0} \times \frac{M_0}{M}\times \frac{T_0}{T} \qquad \Rightarrow \qquad V_n = V_{n,0} \times \sqrt {\frac{P}{P_0} \times \frac{M_0}{M}\times \frac{T_0}{T}}</math>
 
 
https://af.wikipedia.org/wiki/Vloeimeetskyf
 
 
===Bylaag E: Skakel formule om na meer algemene eenhede===
 
====Algemene formule====
 
Die algemene formule vir die vloei deur 'n meetskyf word soos volg gegee:
 
{| class="wikitable"
|-align=center
|
<math>Q_{(m3/s)} = C A_o \sqrt{2 \Delta P_{(Pa)} \over \rho}</math>
|}
 
Die algemene formule kan soos volg omgeskakel word na meer algemene eenhede soos:
 
* <math>V</math> in m<sup>3</sup>/h in plaas van m<sup>3</sup>/s
* <math>\Delta P</math> in kPa in plaas van Pa
* Gaatjiediameter <math>d_o</math> in mm in plaas van <math>A_o</math> in m<sup>2</sup>
* <math>h_w</math> as mm water in plaas van druk
* <math>SG</math> in plaas van <math>\rho</math>
 
<math>\rho</math> bly steeds in kg/m<sup>3</sup>:
 
====Volumevloeitempo (V), gaatjiediameter (d<sub>o</sub>), drukval (&Delta;P) en digtheid (&rho;) ====
 
<math>V</math> in m<sup>3</sup>/h, <math>\Delta P</math> in kPa, gaatjiediameter <math>d_o</math> in mm en <math>\rho</math> in kg/m<sup>3</sup>:
 
 
:<math>\frac{V}{3600} = C \left[\frac{\pi}{4}\left(\frac{d_o}{1000}\right)^2 \right] \sqrt{2 \Delta P \times 1000 \over \rho}</math>
 
 
:<math>V = 0.0028274 C d_o^2 \sqrt{2000 \Delta P \over \rho}</math>
 
{| class="wikitable"
|-align=center
|
<math>V = C d_o^2 \sqrt{\Delta P \over 62.544\rho}</math> {{spaces|10}} of {{spaces|10}} <math>\Delta P = \frac{62.243 \rho}{1} \left ( {V \over C d_o^2} \right )^2</math>
|}
 
 
====Massavloeitempo (W), gaatjiediameter (d<sub>o</sub>), drukval (&Delta;P) en digtheid (&rho;) ====
 
Indien <math>W = \rho V</math>, dan:
 
:<math>\frac{W}{\rho} = C d_o^2 \sqrt{\Delta P \over 62.544\rho}</math>
 
{| class="wikitable"
|-align=center
|
<math>W = C d_o^2 \sqrt{\rho \cdot \Delta P \over 62.544}</math> {{spaces|10}} of {{spaces|10}} <math>\Delta P = \frac{62.243}{\rho} \left ( {W \over C d_o^2} \right )^2</math>
|}
 
====Volumevloeitempo (V), gaatjiediameter (d<sub>o</sub>), drukval (h<sub>w</sub>) en vloeistof SG) ====
 
As:
 
:<math>Q \qquad \Rightarrow \qquad \frac{V}{3600}</math>
 
:<math>A_o = \frac{\pi}{4}\left(\frac{d_o}{1000}\right)^2</math>
 
:<math>\Delta P_{(Pa)} = \rho g \frac{h_w}{1000} = \frac{1000 \times 9.81 \times h_w}{1000} = 9.81 \times h_w</math>
 
:<math>SG = \frac{\rho}{\rho_{van\ water\ by\ 4^\circ C}} \qquad \Rightarrow \qquad \rho = 1000 \times SG</math>
 
Dan is:
 
:<math>\frac{V}{3600} = C \left[\frac{\pi}{4}\left(\frac{d_o}{1000}\right)^2 \right] \sqrt{2 \times 9.81 \times h_w \over 1000 \times SG}</math>
 
 
:::<math>\frac{3600 \times \pi}{4 \times 1000000} \times \sqrt{\frac{2 \times 9.81}{1000}} = 0.00039604</math>
 
{| class="wikitable"
|-align=center
|
<math>V = 0.00039604 C d_o^2 \sqrt{h_w \over SG}</math>
|}
 
== Verwysings ==