Warmtekapasiteit: Verskil tussen weergawes

<math>Q = \int_{T_1800}^{T_2400} 9.01 + 0.00202T + 1.34 \times 10^{-7}T^2 - \frac{117300}{T^2} \, dT</math>

<math> \left ( 9.01T + \frac{0.00202}{2}T^2 + \frac{1.34 \times 10^{-7}}{3} T^3 - \frac{117300}{-1} T^{-1} \right ) |_{800}^{400}</math>

<math> \left | A \right )|_800^200 </math>